If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x(2x-6)=x+4
We move all terms to the left:
9x(2x-6)-(x+4)=0
We multiply parentheses
18x^2-54x-(x+4)=0
We get rid of parentheses
18x^2-54x-x-4=0
We add all the numbers together, and all the variables
18x^2-55x-4=0
a = 18; b = -55; c = -4;
Δ = b2-4ac
Δ = -552-4·18·(-4)
Δ = 3313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{3313}}{2*18}=\frac{55-\sqrt{3313}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{3313}}{2*18}=\frac{55+\sqrt{3313}}{36} $
| 5h-10=h+9 | | 11x2-16x+6=0 | | 12x^2+27x+15=0 | | 3x(2x)=48 | | 3/5p+1/5(40-p=0) | | 3x-5=6×+10 | | 7=8q–9q | | 4x-3=6+2 | | 4g+-9=-36 | | 2x+8/3x+8=4/5 | | 1/x=0.30 | | 0.333=39/x | | 10+3p=13 | | 8.4+0.14x=0.32x | | 2x-1=14+1 | | 3+u=3 | | (4x-3)(2x+1)=4(x-3)(2x-5) | | 1.2x+6=-1.3 | | 7c+40=-3c | | 2.25–11j–7.75+1.5j=0.5j–1.j=–0.45 | | 2(x+4)-10=36-14 | | 2(2+7)=3(3+x) | | 14p-6=9p/34 | | 7a-8=3a+4 | | 2*(x+9)=3*(x-3) | | 5-4(y+1(=-3 | | 45=(2x+3) | | -3(1b)=72 | | 6=3(y−7) | | 3(y−7)=6 | | -7(-3v+5)-5v=4(v-4)-5 | | -2(y-8)=3y-19 |