If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x(3x-1)=15
We move all terms to the left:
9x(3x-1)-(15)=0
We multiply parentheses
27x^2-9x-15=0
a = 27; b = -9; c = -15;
Δ = b2-4ac
Δ = -92-4·27·(-15)
Δ = 1701
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1701}=\sqrt{81*21}=\sqrt{81}*\sqrt{21}=9\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9\sqrt{21}}{2*27}=\frac{9-9\sqrt{21}}{54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9\sqrt{21}}{2*27}=\frac{9+9\sqrt{21}}{54} $
| 6+14=-5(3x-4) | | 136.74=39.99+0.45(x-450) | | 2–x=x–2 | | t+22+7t=3(4t-6) | | 4x-85=5x-93 | | 12x-15=6x+6 | | -4x2+8=24 | | 4n^2-4n-63=0 | | 2x+5+3(x+4)=10x37 | | 6x-45=2x+12 | | |x-12|=40 | | 3(u+5)/11=6 | | 2(x+12)=6x+12 | | 270=50+10(x-65) | | 6x-5x=13+3x | | 3/4(z+8)=-9 | | -22r=1-23r | | 127-y=281 | | 11y+18=10y+18 | | -12=10x-2(3-x) | | 12+8=-4(2x-5) | | 4=-2(x+2)-4(2x+8) | | Y-4(3-4y)=3,5 | | 5a+1=17-3a | | -9(8-q)-13=5 | | 10+2v+8v-64=-2v-6v | | 16+4p=4-p | | 7(s+2)=-7 | | 15x-25=5x+5 | | 5v-5+2(3v+6)=-5(v+1) | | 3(p+7)=15 | | -14=-2+3b |