9x(3x-3)=9+3

Solution for 9x(3x-3)=9+3 equation:

9x(3x-3)=9+3

We move all terms to the left:

9x(3x-3)-(9+3)=0

We add all the numbers together, and all the variables

9x(3x-3)-12=0

We multiply parentheses

27x^2-27x-12=0

a = 27; b = -27; c = -12;
Δ = b2-4ac
Δ = -272-4·27·(-12)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-45}{2*27}=\frac{-18}{54}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+45}{2*27}=\frac{72}{54}
=1+1/3
$