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9x(4x-1)/2x=15
We move all terms to the left:
9x(4x-1)/2x-(15)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
9x(4x-1)-15*2x=0
We multiply parentheses
36x^2-9x-15*2x=0
Wy multiply elements
36x^2-9x-30x=0
We add all the numbers together, and all the variables
36x^2-39x=0
a = 36; b = -39; c = 0;
Δ = b2-4ac
Δ = -392-4·36·0
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-39}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+39}{2*36}=\frac{78}{72} =1+1/12 $
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