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9x(5-3)=(9x)-(9x)
We move all terms to the left:
9x(5-3)-((9x)-(9x))=0
We add all the numbers together, and all the variables
9x2-0=0
We add all the numbers together, and all the variables
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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