9x(5/2)-99=0

Solution for 9x(5/2)-99=0 equation:

9x(5/2)-99=0

We add all the numbers together, and all the variables

9x(+5/2)-99=0

We multiply parentheses

45x^2-99=0

a = 45; b = 0; c = -99;
Δ = b2-4ac
Δ = 02-4·45·(-99)
Δ = 17820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17820}=\sqrt{324*55}=\sqrt{324}*\sqrt{55}=18\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{55}}{2*45}=\frac{0-18\sqrt{55}}{90}
=-\frac{18\sqrt{55}}{90}
=-\frac{\sqrt{55}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{55}}{2*45}=\frac{0+18\sqrt{55}}{90}
=\frac{18\sqrt{55}}{90}
=\frac{\sqrt{55}}{5}
$