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9x(5x-4)=12(2x+5)
We move all terms to the left:
9x(5x-4)-(12(2x+5))=0
We multiply parentheses
45x^2-36x-(12(2x+5))=0
We calculate terms in parentheses: -(12(2x+5)), so:We get rid of parentheses
12(2x+5)
We multiply parentheses
24x+60
Back to the equation:
-(24x+60)
45x^2-36x-24x-60=0
We add all the numbers together, and all the variables
45x^2-60x-60=0
a = 45; b = -60; c = -60;
Δ = b2-4ac
Δ = -602-4·45·(-60)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-120}{2*45}=\frac{-60}{90} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+120}{2*45}=\frac{180}{90} =2 $
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