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9x(x+23)=0
We multiply parentheses
9x^2+207x=0
a = 9; b = 207; c = 0;
Δ = b2-4ac
Δ = 2072-4·9·0
Δ = 42849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42849}=207$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(207)-207}{2*9}=\frac{-414}{18} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(207)+207}{2*9}=\frac{0}{18} =0 $
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