9x(x+8)-4(x+8)=0

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Solution for 9x(x+8)-4(x+8)=0 equation:



9x(x+8)-4(x+8)=0
We multiply parentheses
9x^2+72x-4x-32=0
We add all the numbers together, and all the variables
9x^2+68x-32=0
a = 9; b = 68; c = -32;
Δ = b2-4ac
Δ = 682-4·9·(-32)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-76}{2*9}=\frac{-144}{18} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+76}{2*9}=\frac{8}{18} =4/9 $

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