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9x(x-4)=-36
We move all terms to the left:
9x(x-4)-(-36)=0
We add all the numbers together, and all the variables
9x(x-4)+36=0
We multiply parentheses
9x^2-36x+36=0
a = 9; b = -36; c = +36;
Δ = b2-4ac
Δ = -362-4·9·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{36}{18}=2$
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