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9x(x-4)=4(1-9x)
We move all terms to the left:
9x(x-4)-(4(1-9x))=0
We add all the numbers together, and all the variables
9x(x-4)-(4(-9x+1))=0
We multiply parentheses
9x^2-36x-(4(-9x+1))=0
We calculate terms in parentheses: -(4(-9x+1)), so:We get rid of parentheses
4(-9x+1)
We multiply parentheses
-36x+4
Back to the equation:
-(-36x+4)
9x^2-36x+36x-4=0
We add all the numbers together, and all the variables
9x^2-4=0
a = 9; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·9·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*9}=\frac{-12}{18} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*9}=\frac{12}{18} =2/3 $
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