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9x(x-4)=45
We move all terms to the left:
9x(x-4)-(45)=0
We multiply parentheses
9x^2-36x-45=0
a = 9; b = -36; c = -45;
Δ = b2-4ac
Δ = -362-4·9·(-45)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-54}{2*9}=\frac{-18}{18} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+54}{2*9}=\frac{90}{18} =5 $
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