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9x*x+7x=4
We move all terms to the left:
9x*x+7x-(4)=0
We add all the numbers together, and all the variables
7x+9x*x-4=0
Wy multiply elements
9x^2+7x-4=0
a = 9; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·9·(-4)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{193}}{2*9}=\frac{-7-\sqrt{193}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{193}}{2*9}=\frac{-7+\sqrt{193}}{18} $
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