9x+(7(12-x)/3)=48

Solution for 9x+(7(12-x)/3)=48 equation:

9x+(7(12-x)/3)=48

We move all terms to the left:

9x+(7(12-x)/3)-(48)=0

We add all the numbers together, and all the variables

9x+(7(-1x+12)/3)-48=0

We multiply all the terms by the denominator


9x*3)+(7(-1x+12)-48*3)=0

We add all the numbers together, and all the variables

9x*3)+(7(-1x+12)=0

Wy multiply elements

27x^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{54}=0$