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9x+-4(x-3)=72
We move all terms to the left:
9x+-4(x-3)-(72)=0
determiningTheFunctionDomain 9x-4(x-3)-72+=0
We add all the numbers together, and all the variables
9x-4(x-3)=0
We multiply parentheses
9x-4x+12=0
We add all the numbers together, and all the variables
5x+12=0
We move all terms containing x to the left, all other terms to the right
5x=-12
x=-12/5
x=-2+2/5
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