9x+1-6(-2x-2)=3(x-1)

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Solution for 9x+1-6(-2x-2)=3(x-1) equation: 



9x+1-6(-2x-2)=3(x-1)

We move all terms to the left:

9x+1-6(-2x-2)-(3(x-1))=0

We multiply parentheses

9x+12x-(3(x-1))+12+1=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

21x-(3x-3)+13=0

We get rid of parentheses

21x-3x+3+13=0

We add all the numbers together, and all the variables

18x+16=0

We move all terms containing x to the left, all other terms to the right

18x=-16

x=-16/18

x=-8/9

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