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9x+12-3x=3(2x+4)
We move all terms to the left:
9x+12-3x-(3(2x+4))=0
We add all the numbers together, and all the variables
6x-(3(2x+4))+12=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
6x-6x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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