9x+12=6(x+3)+3(x-2)

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Solution for 9x+12=6(x+3)+3(x-2) equation: 



9x+12=6(x+3)+3(x-2)

We move all terms to the left:

9x+12-(6(x+3)+3(x-2))=0



We calculate terms in parentheses: -(6(x+3)+3(x-2)), so:

6(x+3)+3(x-2)

We multiply parentheses

6x+3x+18-6

We add all the numbers together, and all the variables

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

9x-9x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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