9x+2/5(10-30x)-11=-1/4(12x-28)

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Solution for 9x+2/5(10-30x)-11=-1/4(12x-28) equation: 



9x+2/5(10-30x)-11=-1/4(12x-28)

We move all terms to the left:

9x+2/5(10-30x)-11-(-1/4(12x-28))=0



Domain of the equation: 5(10-30x)!=0

x∈R





Domain of the equation: 4(12x-28))!=0

x∈R



We add all the numbers together, and all the variables

9x+2/5(-30x+10)-(-1/4(12x-28))-11=0

We calculate fractions


9x+(8x1/(5(-30x+10)*4(12x-28)))+(-(-5x0)/(5(-30x+10)*4(12x-28)))-11=0



We calculate terms in parentheses: +(8x1/(5(-30x+10)*4(12x-28))), so:

8x1/(5(-30x+10)*4(12x-28))

We multiply all the terms by the denominator


8x1

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-(-5x0)/(5(-30x+10)*4(12x-28))), so:

-(-5x0)/(5(-30x+10)*4(12x-28))

We add all the numbers together, and all the variables

-(-5x)/(5(-30x+10)*4(12x-28))

We multiply all the terms by the denominator


-(-5x)

We get rid of parentheses

5x

Back to the equation:

+(5x)



We add all the numbers together, and all the variables

22x-11=0

We move all terms containing x to the left, all other terms to the right

22x=11

x=11/22

x=1/2

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