9x+27=2(4x-7)+10

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Solution for 9x+27=2(4x-7)+10 equation: 



9x+27=2(4x-7)+10

We move all terms to the left:

9x+27-(2(4x-7)+10)=0



We calculate terms in parentheses: -(2(4x-7)+10), so:

2(4x-7)+10

We multiply parentheses

8x-14+10

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

9x-8x+4+27=0

We add all the numbers together, and all the variables

x+31=0

We move all terms containing x to the left, all other terms to the right

x=-31

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