9x+27=2(4x-7)+10

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Solution for 9x+27=2(4x-7)+10 equation:



9x+27=2(4x-7)+10
We move all terms to the left:
9x+27-(2(4x-7)+10)=0
We calculate terms in parentheses: -(2(4x-7)+10), so:
2(4x-7)+10
We multiply parentheses
8x-14+10
We add all the numbers together, and all the variables
8x-4
Back to the equation:
-(8x-4)
We get rid of parentheses
9x-8x+4+27=0
We add all the numbers together, and all the variables
x+31=0
We move all terms containing x to the left, all other terms to the right
x=-31

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