9x+3(4+2x)=15(x+1)-3

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Solution for 9x+3(4+2x)=15(x+1)-3 equation: 



9x+3(4+2x)=15(x+1)-3

We move all terms to the left:

9x+3(4+2x)-(15(x+1)-3)=0

We add all the numbers together, and all the variables

9x+3(2x+4)-(15(x+1)-3)=0

We multiply parentheses

9x+6x-(15(x+1)-3)+12=0



We calculate terms in parentheses: -(15(x+1)-3), so:

15(x+1)-3

We multiply parentheses

15x+15-3

We add all the numbers together, and all the variables

15x+12

Back to the equation:

-(15x+12)



We add all the numbers together, and all the variables

15x-(15x+12)+12=0

We get rid of parentheses

15x-15x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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