9x+3(x+3)=3x+2(3x+9)

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Solution for 9x+3(x+3)=3x+2(3x+9) equation: 



9x+3(x+3)=3x+2(3x+9)

We move all terms to the left:

9x+3(x+3)-(3x+2(3x+9))=0

We multiply parentheses

9x+3x-(3x+2(3x+9))+9=0



We calculate terms in parentheses: -(3x+2(3x+9)), so:

3x+2(3x+9)

We multiply parentheses

3x+6x+18

We add all the numbers together, and all the variables

9x+18

Back to the equation:

-(9x+18)



We add all the numbers together, and all the variables

12x-(9x+18)+9=0

We get rid of parentheses

12x-9x-18+9=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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