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9x+3(x+4)=2(6x+1)
We move all terms to the left:
9x+3(x+4)-(2(6x+1))=0
We multiply parentheses
9x+3x-(2(6x+1))+12=0
We calculate terms in parentheses: -(2(6x+1)), so:We add all the numbers together, and all the variables
2(6x+1)
We multiply parentheses
12x+2
Back to the equation:
-(12x+2)
12x-(12x+2)+12=0
We get rid of parentheses
12x-12x-2+12=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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