9x+3(x-1)=7(2+x)-4

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Solution for 9x+3(x-1)=7(2+x)-4 equation: 



9x+3(x-1)=7(2+x)-4

We move all terms to the left:

9x+3(x-1)-(7(2+x)-4)=0

We add all the numbers together, and all the variables

9x+3(x-1)-(7(x+2)-4)=0

We multiply parentheses

9x+3x-(7(x+2)-4)-3=0



We calculate terms in parentheses: -(7(x+2)-4), so:

7(x+2)-4

We multiply parentheses

7x+14-4

We add all the numbers together, and all the variables

7x+10

Back to the equation:

-(7x+10)



We add all the numbers together, and all the variables

12x-(7x+10)-3=0

We get rid of parentheses

12x-7x-10-3=0

We add all the numbers together, and all the variables

5x-13=0

We move all terms containing x to the left, all other terms to the right

5x=13

x=13/5

x=2+3/5

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