9x+3+11x-17=2(7x-5)+46

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Solution for 9x+3+11x-17=2(7x-5)+46 equation: 



9x+3+11x-17=2(7x-5)+46

We move all terms to the left:

9x+3+11x-17-(2(7x-5)+46)=0

We add all the numbers together, and all the variables

20x-(2(7x-5)+46)-14=0



We calculate terms in parentheses: -(2(7x-5)+46), so:

2(7x-5)+46

We multiply parentheses

14x-10+46

We add all the numbers together, and all the variables

14x+36

Back to the equation:

-(14x+36)



We get rid of parentheses

20x-14x-36-14=0

We add all the numbers together, and all the variables

6x-50=0

We move all terms containing x to the left, all other terms to the right

6x=50

x=50/6

x=8+1/3

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