9x+3+3x+12=4(2x-4)

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Solution for 9x+3+3x+12=4(2x-4) equation: 



9x+3+3x+12=4(2x-4)

We move all terms to the left:

9x+3+3x+12-(4(2x-4))=0

We add all the numbers together, and all the variables

12x-(4(2x-4))+15=0



We calculate terms in parentheses: -(4(2x-4)), so:

4(2x-4)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

12x-8x+16+15=0

We add all the numbers together, and all the variables

4x+31=0

We move all terms containing x to the left, all other terms to the right

4x=-31

x=-31/4

x=-7+3/4

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