9x+3-(x-1)=6(x+10)

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Solution for 9x+3-(x-1)=6(x+10) equation:



9x+3-(x-1)=6(x+10)
We move all terms to the left:
9x+3-(x-1)-(6(x+10))=0
We get rid of parentheses
9x-x-(6(x+10))+1+3=0
We calculate terms in parentheses: -(6(x+10)), so:
6(x+10)
We multiply parentheses
6x+60
Back to the equation:
-(6x+60)
We add all the numbers together, and all the variables
8x-(6x+60)+4=0
We get rid of parentheses
8x-6x-60+4=0
We add all the numbers together, and all the variables
2x-56=0
We move all terms containing x to the left, all other terms to the right
2x=56
x=56/2
x=28

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