9x+3-3(-2x-3)=3(x-1)

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Solution for 9x+3-3(-2x-3)=3(x-1) equation:



9x+3-3(-2x-3)=3(x-1)
We move all terms to the left:
9x+3-3(-2x-3)-(3(x-1))=0
We multiply parentheses
9x+6x-(3(x-1))+9+3=0
We calculate terms in parentheses: -(3(x-1)), so:
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
We add all the numbers together, and all the variables
15x-(3x-3)+12=0
We get rid of parentheses
15x-3x+3+12=0
We add all the numbers together, and all the variables
12x+15=0
We move all terms containing x to the left, all other terms to the right
12x=-15
x=-15/12
x=-1+1/4

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