9x+3-3(-2x-3)=3(x-1)

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Solution for 9x+3-3(-2x-3)=3(x-1) equation: 



9x+3-3(-2x-3)=3(x-1)

We move all terms to the left:

9x+3-3(-2x-3)-(3(x-1))=0

We multiply parentheses

9x+6x-(3(x-1))+9+3=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

15x-(3x-3)+12=0

We get rid of parentheses

15x-3x+3+12=0

We add all the numbers together, and all the variables

12x+15=0

We move all terms containing x to the left, all other terms to the right

12x=-15

x=-15/12

x=-1+1/4

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