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9x+3-5x=4(x+3)-5
We move all terms to the left:
9x+3-5x-(4(x+3)-5)=0
We add all the numbers together, and all the variables
4x-(4(x+3)-5)+3=0
We calculate terms in parentheses: -(4(x+3)-5), so:We get rid of parentheses
4(x+3)-5
We multiply parentheses
4x+12-5
We add all the numbers together, and all the variables
4x+7
Back to the equation:
-(4x+7)
4x-4x-7+3=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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