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9x+3-x-1=6(x+10)
We move all terms to the left:
9x+3-x-1-(6(x+10))=0
We add all the numbers together, and all the variables
8x-(6(x+10))+2=0
We calculate terms in parentheses: -(6(x+10)), so:We get rid of parentheses
6(x+10)
We multiply parentheses
6x+60
Back to the equation:
-(6x+60)
8x-6x-60+2=0
We add all the numbers together, and all the variables
2x-58=0
We move all terms containing x to the left, all other terms to the right
2x=58
x=58/2
x=29
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