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9x+3=3(x-1)+12
We move all terms to the left:
9x+3-(3(x-1)+12)=0
We calculate terms in parentheses: -(3(x-1)+12), so:We get rid of parentheses
3(x-1)+12
We multiply parentheses
3x-3+12
We add all the numbers together, and all the variables
3x+9
Back to the equation:
-(3x+9)
9x-3x-9+3=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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