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9x+3x-10=3(3-x+1)
We move all terms to the left:
9x+3x-10-(3(3-x+1))=0
We add all the numbers together, and all the variables
9x+3x-(3(-1x+4))-10=0
We add all the numbers together, and all the variables
12x-(3(-1x+4))-10=0
We calculate terms in parentheses: -(3(-1x+4)), so:We get rid of parentheses
3(-1x+4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
12x+3x-12-10=0
We add all the numbers together, and all the variables
15x-22=0
We move all terms containing x to the left, all other terms to the right
15x=22
x=22/15
x=1+7/15
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