9x+3x-10=3(3x+10)

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Solution for 9x+3x-10=3(3x+10) equation: 



9x+3x-10=3(3x+10)

We move all terms to the left:

9x+3x-10-(3(3x+10))=0

We add all the numbers together, and all the variables

12x-(3(3x+10))-10=0



We calculate terms in parentheses: -(3(3x+10)), so:

3(3x+10)

We multiply parentheses

9x+30

Back to the equation:

-(9x+30)



We get rid of parentheses

12x-9x-30-10=0

We add all the numbers together, and all the variables

3x-40=0

We move all terms containing x to the left, all other terms to the right

3x=40

x=40/3

x=13+1/3

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