9x+3x-1=2(3x+x)-10

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Solution for 9x+3x-1=2(3x+x)-10 equation: 



9x+3x-1=2(3x+x)-10

We move all terms to the left:

9x+3x-1-(2(3x+x)-10)=0

We add all the numbers together, and all the variables

9x+3x-(2(+4x)-10)-1=0

We add all the numbers together, and all the variables

12x-(2(+4x)-10)-1=0



We calculate terms in parentheses: -(2(+4x)-10), so:

2(+4x)-10

We multiply parentheses

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

12x-8x+10-1=0

We add all the numbers together, and all the variables

4x+9=0

We move all terms containing x to the left, all other terms to the right

4x=-9

x=-9/4

x=-2+1/4

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