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9x+3x-9=3(3x+1)
We move all terms to the left:
9x+3x-9-(3(3x+1))=0
We add all the numbers together, and all the variables
12x-(3(3x+1))-9=0
We calculate terms in parentheses: -(3(3x+1)), so:We get rid of parentheses
3(3x+1)
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
12x-9x-3-9=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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