9x+4(x-2)=8(x+2)-x

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Solution for 9x+4(x-2)=8(x+2)-x equation: 



9x+4(x-2)=8(x+2)-x

We move all terms to the left:

9x+4(x-2)-(8(x+2)-x)=0

We multiply parentheses

9x+4x-(8(x+2)-x)-8=0



We calculate terms in parentheses: -(8(x+2)-x), so:

8(x+2)-x

We add all the numbers together, and all the variables

-1x+8(x+2)

We multiply parentheses

-1x+8x+16

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

13x-(7x+16)-8=0

We get rid of parentheses

13x-7x-16-8=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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