9x+5(10-8x)=-3-7(4x+1)

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Solution for 9x+5(10-8x)=-3-7(4x+1) equation: 



9x+5(10-8x)=-3-7(4x+1)

We move all terms to the left:

9x+5(10-8x)-(-3-7(4x+1))=0

We add all the numbers together, and all the variables

9x+5(-8x+10)-(-3-7(4x+1))=0

We multiply parentheses

9x-40x-(-3-7(4x+1))+50=0



We calculate terms in parentheses: -(-3-7(4x+1)), so:

-3-7(4x+1)

determiningTheFunctionDomain
-7(4x+1)-3

We multiply parentheses

-28x-7-3

We add all the numbers together, and all the variables

-28x-10

Back to the equation:

-(-28x-10)



We add all the numbers together, and all the variables

-31x-(-28x-10)+50=0

We get rid of parentheses

-31x+28x+10+50=0

We add all the numbers together, and all the variables

-3x+60=0

We move all terms containing x to the left, all other terms to the right

-3x=-60

x=-60/-3

x=+20

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