9x+5(2800-(9x/5))=14000

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Solution for 9x+5(2800-(9x/5))=14000 equation:



9x+5(2800-(9x/5))=14000
We move all terms to the left:
9x+5(2800-(9x/5))-(14000)=0
We add all the numbers together, and all the variables
9x+5(2800-(+9x/5))-14000=0
We multiply all the terms by the denominator
9x*5))+5(2800-(+9x-14000*5))=0
We add all the numbers together, and all the variables
9x*5))+5(2800-(9x-70000))=0
We add all the numbers together, and all the variables
9x*5))+5(2800-(9x=0
Wy multiply elements
45x^2=0
a = 45; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·45·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{90}=0$

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