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9x+6=3(2+3x)
We move all terms to the left:
9x+6-(3(2+3x))=0
We add all the numbers together, and all the variables
9x-(3(3x+2))+6=0
We calculate terms in parentheses: -(3(3x+2)), so:We get rid of parentheses
3(3x+2)
We multiply parentheses
9x+6
Back to the equation:
-(9x+6)
9x-9x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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