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9x+6=3(3x^2)
We move all terms to the left:
9x+6-(3(3x^2))=0
determiningTheFunctionDomain 9x-33x^2+6=0
We add all the numbers together, and all the variables
-33x^2+9x+6=0
a = -33; b = 9; c = +6;
Δ = b2-4ac
Δ = 92-4·(-33)·6
Δ = 873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{873}=\sqrt{9*97}=\sqrt{9}*\sqrt{97}=3\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{97}}{2*-33}=\frac{-9-3\sqrt{97}}{-66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{97}}{2*-33}=\frac{-9+3\sqrt{97}}{-66} $
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