9x+9=(1/3)(3x+3)

Solution for 9x+9=(1/3)(3x+3) equation:

9x+9=(1/3)(3x+3)

We move all terms to the left:

9x+9-((1/3)(3x+3))=0


Domain of the equation: 3)(3x+3))!=0

x∈R


We add all the numbers together, and all the variables

9x-((+1/3)(3x+3))+9=0

We multiply parentheses ..

-((+3x^2+1/3*3))+9x+9=0

We multiply all the terms by the denominator


-((+3x^2+1+9x*3*3))+9*3*3))=0


We calculate terms in parentheses: -((+3x^2+1+9x*3*3)), so:

(+3x^2+1+9x*3*3)

We get rid of parentheses

3x^2+9x*3*3+1

Wy multiply elements

3x^2+81x*3+1

Wy multiply elements

3x^2+243x+1

Back to the equation:

-(3x^2+243x+1)


We add all the numbers together, and all the variables

-(3x^2+243x+1)=0

We get rid of parentheses

-3x^2-243x-1=0

a = -3; b = -243; c = -1;
Δ = b2-4ac
Δ = -2432-4·(-3)·(-1)
Δ = 59037
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-243)-\sqrt{59037}}{2*-3}=\frac{243-\sqrt{59037}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-243)+\sqrt{59037}}{2*-3}=\frac{243+\sqrt{59037}}{-6}
$