9x+x-4(x+3)=6(x-2)

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Solution for 9x+x-4(x+3)=6(x-2) equation:


Simplifying
9x + x + -4(x + 3) = 6(x + -2)

Reorder the terms:
9x + x + -4(3 + x) = 6(x + -2)
9x + x + (3 * -4 + x * -4) = 6(x + -2)
9x + x + (-12 + -4x) = 6(x + -2)

Reorder the terms:
-12 + 9x + x + -4x = 6(x + -2)

Combine like terms: 9x + x = 10x
-12 + 10x + -4x = 6(x + -2)

Combine like terms: 10x + -4x = 6x
-12 + 6x = 6(x + -2)

Reorder the terms:
-12 + 6x = 6(-2 + x)
-12 + 6x = (-2 * 6 + x * 6)
-12 + 6x = (-12 + 6x)

Add '12' to each side of the equation.
-12 + 12 + 6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
0 + 6x = -12 + 12 + 6x
6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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