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9x-(2x+1)=3(x-3)-1
We move all terms to the left:
9x-(2x+1)-(3(x-3)-1)=0
We get rid of parentheses
9x-2x-(3(x-3)-1)-1=0
We calculate terms in parentheses: -(3(x-3)-1), so:We add all the numbers together, and all the variables
3(x-3)-1
We multiply parentheses
3x-9-1
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
7x-(3x-10)-1=0
We get rid of parentheses
7x-3x+10-1=0
We add all the numbers together, and all the variables
4x+9=0
We move all terms containing x to the left, all other terms to the right
4x=-9
x=-9/4
x=-2+1/4
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