9x-(2x-3)=3(x+1)+4x

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Solution for 9x-(2x-3)=3(x+1)+4x equation:


Simplifying
9x + -1(2x + -3) = 3(x + 1) + 4x

Reorder the terms:
9x + -1(-3 + 2x) = 3(x + 1) + 4x
9x + (-3 * -1 + 2x * -1) = 3(x + 1) + 4x
9x + (3 + -2x) = 3(x + 1) + 4x

Reorder the terms:
3 + 9x + -2x = 3(x + 1) + 4x

Combine like terms: 9x + -2x = 7x
3 + 7x = 3(x + 1) + 4x

Reorder the terms:
3 + 7x = 3(1 + x) + 4x
3 + 7x = (1 * 3 + x * 3) + 4x
3 + 7x = (3 + 3x) + 4x

Combine like terms: 3x + 4x = 7x
3 + 7x = 3 + 7x

Add '-3' to each side of the equation.
3 + -3 + 7x = 3 + -3 + 7x

Combine like terms: 3 + -3 = 0
0 + 7x = 3 + -3 + 7x
7x = 3 + -3 + 7x

Combine like terms: 3 + -3 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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