9x-(3x-12)=4(2x+1)+(7x-3)

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Solution for 9x-(3x-12)=4(2x+1)+(7x-3) equation: 



9x-(3x-12)=4(2x+1)+(7x-3)

We move all terms to the left:

9x-(3x-12)-(4(2x+1)+(7x-3))=0

We get rid of parentheses

9x-3x-(4(2x+1)+(7x-3))+12=0



We calculate terms in parentheses: -(4(2x+1)+(7x-3)), so:

4(2x+1)+(7x-3)

We multiply parentheses

8x+(7x-3)+4

We get rid of parentheses

8x+7x-3+4

We add all the numbers together, and all the variables

15x+1

Back to the equation:

-(15x+1)



We add all the numbers together, and all the variables

6x-(15x+1)+12=0

We get rid of parentheses

6x-15x-1+12=0

We add all the numbers together, and all the variables

-9x+11=0

We move all terms containing x to the left, all other terms to the right

-9x=-11

x=-11/-9

x=1+2/9

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