9x-(3x-2)=4(2x+1)+(7x-3)

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Solution for 9x-(3x-2)=4(2x+1)+(7x-3) equation:



9x-(3x-2)=4(2x+1)+(7x-3)
We move all terms to the left:
9x-(3x-2)-(4(2x+1)+(7x-3))=0
We get rid of parentheses
9x-3x-(4(2x+1)+(7x-3))+2=0
We calculate terms in parentheses: -(4(2x+1)+(7x-3)), so:
4(2x+1)+(7x-3)
We multiply parentheses
8x+(7x-3)+4
We get rid of parentheses
8x+7x-3+4
We add all the numbers together, and all the variables
15x+1
Back to the equation:
-(15x+1)
We add all the numbers together, and all the variables
6x-(15x+1)+2=0
We get rid of parentheses
6x-15x-1+2=0
We add all the numbers together, and all the variables
-9x+1=0
We move all terms containing x to the left, all other terms to the right
-9x=-1
x=-1/-9
x=1/9

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