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9x-(x-18)=2x(18+x)
We move all terms to the left:
9x-(x-18)-(2x(18+x))=0
We add all the numbers together, and all the variables
9x-(x-18)-(2x(x+18))=0
We get rid of parentheses
9x-x-(2x(x+18))+18=0
We calculate terms in parentheses: -(2x(x+18)), so:We add all the numbers together, and all the variables
2x(x+18)
We multiply parentheses
2x^2+36x
Back to the equation:
-(2x^2+36x)
8x-(2x^2+36x)+18=0
We get rid of parentheses
-2x^2+8x-36x+18=0
We add all the numbers together, and all the variables
-2x^2-28x+18=0
a = -2; b = -28; c = +18;
Δ = b2-4ac
Δ = -282-4·(-2)·18
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{58}}{2*-2}=\frac{28-4\sqrt{58}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{58}}{2*-2}=\frac{28+4\sqrt{58}}{-4} $
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