9x-(x-18)=2x-(-10+x)

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Solution for 9x-(x-18)=2x-(-10+x) equation:



9x-(x-18)=2x-(-10+x)
We move all terms to the left:
9x-(x-18)-(2x-(-10+x))=0
We add all the numbers together, and all the variables
9x-(x-18)-(2x-(x-10))=0
We get rid of parentheses
9x-x-(2x-(x-10))+18=0
We calculate terms in parentheses: -(2x-(x-10)), so:
2x-(x-10)
We get rid of parentheses
2x-x+10
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
We add all the numbers together, and all the variables
8x-(x+10)+18=0
We get rid of parentheses
8x-x-10+18=0
We add all the numbers together, and all the variables
7x+8=0
We move all terms containing x to the left, all other terms to the right
7x=-8
x=-8/7
x=-1+1/7

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