9x-(x-18)=2x-(10+x)

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Solution for 9x-(x-18)=2x-(10+x) equation: 



9x-(x-18)=2x-(10+x)

We move all terms to the left:

9x-(x-18)-(2x-(10+x))=0

We add all the numbers together, and all the variables

9x-(x-18)-(2x-(x+10))=0

We get rid of parentheses

9x-x-(2x-(x+10))+18=0



We calculate terms in parentheses: -(2x-(x+10)), so:

2x-(x+10)

We get rid of parentheses

2x-x-10

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)



We add all the numbers together, and all the variables

8x-(x-10)+18=0

We get rid of parentheses

8x-x+10+18=0

We add all the numbers together, and all the variables

7x+28=0

We move all terms containing x to the left, all other terms to the right

7x=-28

x=-28/7

x=-4

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