9x-(x-18)=2x-(4+x)

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Solution for 9x-(x-18)=2x-(4+x) equation:



9x-(x-18)=2x-(4+x)
We move all terms to the left:
9x-(x-18)-(2x-(4+x))=0
We add all the numbers together, and all the variables
9x-(x-18)-(2x-(x+4))=0
We get rid of parentheses
9x-x-(2x-(x+4))+18=0
We calculate terms in parentheses: -(2x-(x+4)), so:
2x-(x+4)
We get rid of parentheses
2x-x-4
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
We add all the numbers together, and all the variables
8x-(x-4)+18=0
We get rid of parentheses
8x-x+4+18=0
We add all the numbers together, and all the variables
7x+22=0
We move all terms containing x to the left, all other terms to the right
7x=-22
x=-22/7
x=-3+1/7

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