9x-(x-18)=2x-(4+x)

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Solution for 9x-(x-18)=2x-(4+x) equation: 



9x-(x-18)=2x-(4+x)

We move all terms to the left:

9x-(x-18)-(2x-(4+x))=0

We add all the numbers together, and all the variables

9x-(x-18)-(2x-(x+4))=0

We get rid of parentheses

9x-x-(2x-(x+4))+18=0



We calculate terms in parentheses: -(2x-(x+4)), so:

2x-(x+4)

We get rid of parentheses

2x-x-4

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)



We add all the numbers together, and all the variables

8x-(x-4)+18=0

We get rid of parentheses

8x-x+4+18=0

We add all the numbers together, and all the variables

7x+22=0

We move all terms containing x to the left, all other terms to the right

7x=-22

x=-22/7

x=-3+1/7

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